College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Chapter 8 Review - Exercises: 1

Answer

$a_1=\frac{1}{2}$ $a_2=\frac{4}{3}$ $a_3=\frac{9}{4}$ $a_4=\frac{16}{5}$ $a_{10}=\frac{100}{11}$

Work Step by Step

We are given: $a_{n}= \frac{n^{2}}{n+1}$ We evaluate: $a_1= \frac{1^{2}}{1+1}=\frac{1}{2}$ $a_2=\frac{2^{2}}{2+1}=\frac{4}{3}$ $a_3=\frac{3^{2}}{3+1}=\frac{9}{4}$ $a_4= \frac{4^{2}}{4+1}=\frac{16}{5}$ $a_{10}= \frac{10^{2}}{10+1}=\frac{100}{11}$
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