Chapter 5, Systems of Equations and Inequalities - Section 5.1 - Systems of Linear Equations in Two Variations - 5.1 Exercises - Page 447: 49

The system has no solution. The system is consistent.

Multiplying the first equation by 24 and the second equation by 1 gives: $8x-6y=48$ $-8x+6y=10$ Adding two equations eliminates both x and y, end up with = 58. We can not make this statement true, so the system has no solution. The system is consistent.