Chapter 5, Systems of Equations and Inequalities - Section 5.1 - Systems of Linear Equations in Two Variations - 5.1 Exercises - Page 447: 48

x=1; y=3

Multiplying the first equation by 6/5 and the second equation by 10 gives: $\frac{156}{5}x-12y=\frac{-24}{5}$ $-6x+12y=30$ Adding two equations: $\frac{126}{5}x=\frac{126}{5} \Rightarrow x=1$ Solve for y: $26(1) -10y = -4 \Rightarrow y=3 $