Answer
$t=\frac{\ln2}{0.085}=8.155~years$
Work Step by Step
$A=Pe^{rt}$
$r=8.5$% $=0.085$
$P=1000$
$A=2000$
$2000=1000e^{0.085t}$
$2=e^{0.085t}$
$\ln2=\ln e^{0.085t}$
$\ln2=0.085t$
$t=\frac{\ln2}{0.085}=8.155$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 405: 93
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