College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.2 - The Natural Exponential Function - 4.2 Exercises - Page 378: 24

Answer

(a) $m(0)=13$ (b) $m(45)=6.62$ kg

Work Step by Step

We are given: $m(t)=13e^{-0.015t}$ (a) We plug in $t=0$: $m(0)=13e^{-0.015*0}=13*1=13$ (b) We plug in $t=45$: $m(45)=13e^{-0.015*45}=13e^{-0.675}=6.62$ kg
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.