Answer
$f(1/2)=2$;
$f(\sqrt5) \approx. 22.195$;
$f(-2)\approx 0.063$;
$f(0.3) \approx. 1.516$
Work Step by Step
Evaluate the function for the given values of $x$ by substituting each $x$ into $f(x)$ then using a calculator to find the exact value.
When x=$\frac{1}{2}$:
$f(x) = 4^x
\\f(1/2)=4^{\frac{1}{2}}
\\f(1/2)=2$
When $x=\sqrt5$:
$f(x) = 4^x
\\f(\sqrt{5}) = 4^{\sqrt5} =
\\f(\sqrt5) \approx. 22.195$
When $x=-2$:
$f(x)=4^x
\\f(-2)=4^{-2}
\\f(-2)\approx 0.063$
When $x=0.3$:
$f(x)=4^x
\\f(0.3) = 4^{0.3}
\\f(0.3) \approx. 1.516$
