College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Test: 3

Answer

(a) $2x=\log_{6}25$ or: $x=\frac{1}{2}\log_{6}25$ (b) $A=e^{3}$

Work Step by Step

(a) We are given: $6^{2x}=25$ This means: $2x=\log_{6}25$ or: $x=\frac{1}{2}\log_{6}25$ (b) $\ln A=3$ We use $e$ to cancel $\ln$: $e^{\ln A}=e^{3}$ $A=e^{3}$
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