College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check: 1

Answer

$f(-1.5)\approx 0.089$ $f(\sqrt{2})\approx 9.739$ $f(2.5)\approx 55.902$

Work Step by Step

We are given: $f(x)=5^{x}$ We evaluate with a calculator: $f(-1.5)\approx 0.089$ $f(\sqrt{2})\approx 9.739$ $f(2.5)\approx 55.902$
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