## College Algebra 7th Edition

g(x) = $\sqrt[5] x$ = $x^{\frac{1}{5}}$ $g(f(x))= g(x^{5})$ ${x^{5}}^{\frac{1}{5}}$ = x $f(g(x)) = f(x^{\frac{1}{5}})$ ${x^{\frac{1}{5}}}^{5}$ = x Since f(g(x)) = g(f(x)), f and g are inverses of each other