College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises: 28

Answer

$g^{-1}(5)$ = 1

Work Step by Step

$g(x) = x^{2} + 4x$, $x\geq2$ Plug in 5 for g(x) (5 is the x value for $g^{-1}(5)$, so it is the y value for g(x)) $5 = x^{2} + 4x$ $0 = x^{2} + 4x - 5$ 0 = (x - 1)(x + 5) x = 1, -5 x = -5 because it is not in the domain of g(x) x value of g(x) equals the y value of $g^{-1}(x)$ $g^{-1}(5)$ = 1
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