Answer
1
Work Step by Step
From the table, we see that: $g(2)=5$ and $g(5)=1$, so we have:
$(g\circ g)(2)=g(g(2))=g(5)=1$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Section 2.7 - Combining Functions - 2.7 Exercises - Page 253: 46
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