Answer
(a) 600
(b) 60
Work Step by Step
We are given: $f(x)=x^3-4x^2$; $x=0$, $x=10$
(a) We calculate the net change:
$f(10)-f(0)=[10^{3}-4(10^{2})]-[0^{3}-4(0^{2})]=(1000-400)-(0-0)=600-0=600$
(b) We calculate the average rate of change:
$\displaystyle \frac{f(10)-f(0)}{10-0}=\frac{600}{10}=60$
