College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises: 17

Answer

(a) 600 (b) 60

Work Step by Step

We are given: $f(x)=x^3-4x^2$; $x=0$, $x=10$ (a) We calculate the net change: $f(10)-f(0)=[10^{3}-4(10^{2})]-[0^{3}-4(0^{2})]=(1000-400)-(0-0)=600-0=600$ (b) We calculate the average rate of change: $\displaystyle \frac{f(10)-f(0)}{10-0}=\frac{600}{10}=60$
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