College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.7 - Solving Inequalities - 1.7 Exercises - Page 149: 88

Answer

At the range of distance $x\gt30$ was the temperature less than 500.

Work Step by Step

$\frac{600,000}{x^2+300}\lt500$ $600,000\lt 500(x^2+300)$, Multiplying both sides by $x^2+300$. $600,000\lt500x^2+150,000$, $450,000\lt500x^2$, $900\lt x^2$, $\pm 30 \lt x$. Since we're solving for distance, only positive answers are relevant. Therefore, at the range of distance $x\gt30$ was the temperature less than 500.
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