Answer
$\frac{a-c}{b}\leq x\lt \frac{2a-c}{b}$
Work Step by Step
$a\leq bx+c<2a$
We subtract $c$ from all sides:
$\displaystyle a-c\leq bx\lt 2a-c$
And divide by $b$:
$\frac{a-c}{b}\leq x\lt \frac{2a-c}{b}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.7 - Solving Inequalities - 1.7 Exercises - Page 149: 78
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