Answer
$(-1,3)$
Work Step by Step
$(x-2)^{2}(x-3)(x+1)\leq0$
These are zero when x=-1, x=2,x=3. These numbers divide the real line into the intervals $(-\infty,-1)(-1,2)(2,3)(3,+\infty)$
Ussing the test points to determine the sign of each factor in each interval: