Answer
The solution set is $(-2,2)$
Work Step by Step
$x^2<4\hspace{0.7cm}{\color{blue}{\text{Given equation}}}$
$\Rightarrow x^2-4<0$
$\Rightarrow (x-2)(x+2)<0\hspace{0.7cm}{\color{blue}{\text{Factor}}}$
The factors of the left-hand side are $x-2$ and $x+2$.
These factors are zero when $x=2$ and $x=-2$.
These numbers divide the real line into the intervals
$(-\infty,-2),(-2,2),(2,\infty)$
From the diagram and hence the inequality involves $
