Answer
$\approx4.63$ mm
Work Step by Step
Let $r$ be the radius of the big sphere. Then, equating the volumes gives:
$V=\frac{4}{3}r^3\pi=\frac{4}{3}2^3\pi+\frac{4}{3}3^3\pi+\frac{4}{3}4^3\pi\\r^3=2^3+3^3+4^3=99\\r=\sqrt[3] {99}\approx4.63~mm$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises - Page 139: 85
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