College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises: 66

Answer

$x=9$, $x=4$

Work Step by Step

$x-5\sqrt{x}+6=0$ We make the substitution $y=\sqrt{x}$. The equation becomes: $y^{2}-5y+6=0$ $(y-3)(y-2)=0$ $y-3=0$ or $y-2=0$ $y=3$ or $y=2$ We find the $x$ solutions with the $y$ solutions: $y=\sqrt{x}$ $x=y^2$ For $y=3$: $x=3^2=9$ For y=2: $x=2^2=4$
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