College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises: 53

Answer

$x=3$ or $x=-1$

Work Step by Step

$x^{6}-26x^{3}-27=0$ We factor and solve: $(x^{3}-27)(x^{3}+1)=0$ $x^{3}-27=0$ or $x^{3}+1=0$ $x^3=27$ or $x^3=-1$ $x=\sqrt[3]{27}=3$ or $x=\sqrt[3]{-1}=-1$
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