Answer
$x=\pm\sqrt2,\pm\sqrt3$
Work Step by Step
We simplify as follows:
$x^{4}-5x^{2}+6=0$
$(x^{2}-2)(x^{2}-3)=0$
$(x-\sqrt2)(x+\sqrt2)(x-\sqrt3)(x+\sqrt3)=0$
$x=\pm\sqrt2,\pm\sqrt3$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises - Page 139: 50
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