Answer
$x=7$
Work Step by Step
$5=\sqrt{4x-3}$
$5^{2}=(\sqrt{4x-3})^{2}$
$25=4x-3$
$25+3=4x$
$4x=28$
$x=28/4=7$
We need to confirm that the solution $x=7$ works in the original equation:
$\sqrt{4(7)-3}=\sqrt{28-3}=\sqrt{25}=5$
Which is true.