College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.3 - Lines - 1.3 Exercises - Page 113: 41

Answer

$y=5$

Work Step by Step

RECALL: (1) Perpendicular lines have slopes whose product is $-1$ (or negative reciprocal slopes). (2) A horizontal line has a slope of $0$ and has an equation of the form $y=k$ where $k$ is the y-coordinate of all the points on the line. (4) Horizontal lines are parallel to each other. The line is parallel to the x-axis. Since the axis is a horizontal line, its slope is $0$. This means that the slope of the line we are looking for is also $0$. The horizontal line we are looking for the equation of passes through $(4, 5)$. The y-coordinate of this point is $5$. Therefore, the equation of the line we are looking for is $y=5$.
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