College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.2 - Graphs of Equations in Two Variables; Circles - 1.2 Exercises - Page 101: 1

Answer

If the point (2,3) is on the graph of an equation in $x$ and $y$, then the equation is satisfied when we replace $x$ by $2$ and $y$ by $3$. The point (2,3) is not on the graph of the equation $2y = x+1$

Work Step by Step

To check that the point (2,3) is not on the graph of the equation $2y = x+1$ we can replace $x$ by $2$ and $y$ by $3$: $$2(3) = 2 + 1 \Leftrightarrow 6 = 3$$ It is false because $6 \neq 3$, so the point (2,3) is not on the graph of the equation $2y = x+1$. Now, to complete the table we can express $y$ in terms of $x$: $$2y = x + 1 \Leftrightarrow y = \frac{x+1}{2} \Leftrightarrow y = \frac{1}{2}x + \frac{1}{2}$$ Finally, just replace each value for $x$ in the table and get a value for $y$. Then complete the graph.
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