College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.10 - Modeling Variation - 1.10 Exercises: 41

Answer

$s=5.33$ mi/h

Work Step by Step

Since $F$ varies jointly with $A$ and the square of $s$, we have: $F=kAs^{2}$ We are given: $F=220$ and $A=40$ and $s=5$, so we have: $220=k*40*5^2$ $220=1000k$ $k=220/1000=0.22$ Therefore: $F=0.22As^2$ Now we plug in $A=28$ and $F=175$ to find $s$: $175=0.220*28*s^{2}$ $175=6.16s^2$ $28.409=s^{2}$ $s=\sqrt{28.4090}=5.33$ mi/h
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