Answer
Point $C$ is closer to point $E$ .
Work Step by Step
$d(E, C)=\sqrt{(-6-(-2))^{2}+(3-1)^{2}}=\sqrt{(-4)^{2}+2^{2}}$
$=\sqrt{16+4}=\sqrt{20}$.
$d(E, D)=\sqrt{(3-(-2))^{2}+(0-1)^{2}}=\sqrt{5^{2}+(-1)^{2}}$
$=\sqrt{25+1}=\sqrt{26}$.
Point $C$ is closer to point $E$ (than point $D$).
