Answer
$-1\pm\frac{\sqrt{2}}{2}i$
Work Step by Step
$2x^{2}+4x+3=0$
We use the quadratic formula ($a=2, b=4, c=3$):
$x=\frac{-4\pm\sqrt{4^{2}-4*2*3}}{2*2}=\frac{-4\pm\sqrt{-8}}{4}=\frac{-4\pm2\sqrt{2}i}{4}=-1\pm\frac{\sqrt{2}}{2}i$
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