## College Algebra 7th Edition

a. $81$ b. $-81$ c. $\frac{1}{81}$ d. $25$ e. $\frac{16}{9}$ f. $8$
a.$(-3)^{4}$ $=( -3 \times-3\times-3\times-3) = 81$ b. $-3^{4}$ $=-(3\times3\times3\times3) = -81$ c.$3^{-4}$ $= \frac{1}{3^{4}} = \frac{1}{81}$ d.$\frac{5^{12}}{5^{10}}$ Subtract the exponents. $=5^{12-10} = 5^{2} = 25$ e. $(\frac{3}{4})^{-2}$ $=\frac{4}{3}^{2} = \frac{4^{2}}{3^{2}} = \frac{16}{9}$ f. $16^{\frac{3}{4}}$ $(\sqrt[4] 16)^{3} = 2^{3} = 8$