College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises: 62

Answer

$x\sqrt[4] 2$

Work Step by Step

$\frac{\sqrt[4] 32x^{5}}{\sqrt[4] 16x}=\sqrt[4] \frac{32x^{5}}{16x}=\sqrt[4] 2x^{4}= \sqrt[4] (x^{4}\times2)=\sqrt[4] x^{4}\times\sqrt[4] 2=x\sqrt[4] 2 $ We know that $\sqrt[4] x^{4}=x$, because $(x)^{4}=x^{4}$.
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