College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises: 58

Answer

$3\sqrt[3]3$

Work Step by Step

$\sqrt[3] 81=\sqrt[3](27\times3)=\sqrt[3]27\times\sqrt[3]3=3\sqrt[3]3$ We know that $\sqrt[3] 27=3$, because $3^{3}=3\times3\times3=27$.
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