College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises: 51

Answer

$\frac{\sqrt6}{3}$

Work Step by Step

$\frac{\sqrt2}{\sqrt 3}=\frac{\sqrt2}{\sqrt 3}\times(\frac{\sqrt 3}{\sqrt 3})=\frac{\sqrt2\times\sqrt 3}{3}=\frac{\sqrt(2\times3)}{3}=\frac{\sqrt6}{3}$
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