College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises: 46

Answer

$4x\sqrt3$

Work Step by Step

$\frac{\sqrt 96x^{3}}{\sqrt 2x}=\sqrt \frac{96x^{3}}{2x}=\sqrt 48x^{2}=\sqrt (16x^{2}\times3)=\sqrt 16x^{2}\times \sqrt3=4x\sqrt3$ We know that $\sqrt 16x^{2}=4x$, because $(4x)^{2}=4^{2}x^{2}=16x^{2}$.
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