## College Algebra (6th Edition)

We are given the expression $\frac{3x+2}{3x+4}+\frac{3x+6}{3x+4}$. Since both terms have a common denominator, we can add these fractions together. $\frac{3x+2}{3x+4}+\frac{3x+6}{3x+4}=\frac{3x+2+3x+6}{3x+4}=\frac{(3x+3x)+(2+6)}{3x+4}=\frac{6x+8}{3x+4}=\frac{2}{1}=2$