College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5: 58

Answer

$(x+4)(x^{2}-4x+16)$

Work Step by Step

If a and b are real numbers, we know that $a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2)}$. Therefore, we know that $x^{3}+64=(x+4)(x^{2}-x\times4+4^{2})=(x+4)(x^{2}-4x+16)$. In this case, $a=x$ and $b=4$.
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