College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5: 56

Answer

$(8x-1)^{2}$

Work Step by Step

If a and b are real numbers, we know that $a^{2}-2ab+b^{2}=(a-b)^{2}$. Therefore, we know that $64x^{2}-16x+1=(8x-1)^{2}$. In this case, $a=8x$ and $b=1$.
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