## College Algebra (6th Edition)

Published by Pearson

# Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5: 40

#### Answer

$(x+12)(x-12)$

#### Work Step by Step

If $a$ and $b$ are real numbers, we know that $a^{2}-b^{2}=(a+b)(a-b)$. In words, the difference of the squares of two terms factors as a product of a sum and a difference of those terms. Therefore, we know that $x^{2}-144=(x+12)(x-12)$. In this case, $a=x$ and $b=12$.

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