College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 82

Answer

$9x^2y^4-16y^2$

Work Step by Step

$$(3xy^2-4y)(3xy^2+4y)$$ The product of the sum and the difference of two terms can be found using this formula: $(a-b)(a+b) = a^2-b^2$. $$=(3xy^2)^2-(4y)^2$$ $$=9x^2y^4-16y^2$$
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