College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 75

Answer

$x^4y^4-6x^2y^2+9$

Work Step by Step

$$(x^2y^2-3)^2$$ To square a binomial, multiply it by itself: $$=(x^2y^2-3)(x^2y^2-3)$$ To multiply two binomials (expressions with two terms) multiply each term in the first binomial by each term in the second binomial:$$=(x^2y^2]times x^2y^2)+[x^2y^2\times (-3)]+(-3\times x^2y^2)+[-3\times (-3)]$$ $$=x^4y^4-3x^2y^2-3x^2y^2+9$$ $$=x^4y^4-6x^2y^2+9$$
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