## College Algebra (6th Edition)

Published by Pearson

# Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 72

#### Answer

$14x^4y^2-19x^2y-3$

#### Work Step by Step

$$(7x^2y+1)(2x^2y-3)$$ To multiply two binomials (expressions with two terms) multiply each term in the first binomial by each term in the second binomial: $$=(7x^2y\times 2x^2y)+[7x^2y\times (-3)]+(1\times 2x^2y)+[1\times (-3)]$$ $$=14x^4y^2-21x^2y+2x^2y-3$$ Combine like terms: $$=14x^4y^2-19x^2y-3$$

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