College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 52

Answer

$x^3+6x^2+12x+8$

Work Step by Step

$$(x+2)^3$$ $$=(x+2)(x+2)(x+2)$$ $$=(x+2)[(x\times x)+(x\times 2)+(2\times x)+(2\times 2)]$$ $$=(x+2)(x^2+2x+2x+4)$$ $$=(x+2)(x^2+4x+4)$$ $$=(x\times x^2)+(x\times 4x)+(x\times 4)+(2\times x^2)+(2\times 4x)+(2\times 4)$$ $$=x^3+4x^2+4x+2x^2+8x+8$$ $$=x^3+6x^2+12x+8$$
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