College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 49

Answer

$49-28x+4x^2$ Note: standard form lists variables first in decreasing order of exponent, so this answer could also be written as: $4x^2-28x+49$.

Work Step by Step

$$(7-2x)^2$$ $$=(7-2x)(7-2x)$$ $$=(7\times 7)+(7\times (-2x))+(-2x\times 7)+(-2x\times (-2x))$$ $$=49-14x-14x+4x^2$$ $$=49-28x+4x^2$$ Note: standard form lists variables first in decreasing order of exponent, so this answer could also be written as: $$4x^2-28x+49$$
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