College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 46

Answer

$x^2-8x+16$

Work Step by Step

$$(x-4)^2$$ $$=(x-4)(x-4)$$ $$=(x\times x)+(x\times (-4))+(-4\times x)+(-4\times (-4))$$ $$=x^2-4x-4x+16$$ $$=x^2-8x+16$$
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