College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 37

Answer

$16x^4-25x^2$

Work Step by Step

$$(4x^2+5x)(4x^2-5x)$$ $$=(4x^2\times 4x^2)+(4x^2\times (-5x))+(5x\times 4x^2)+(5x\times (-5x))$$ $$=16x^4-20x^3+20x^3-25x^2$$ $$=16x^4-25x^2$$
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