College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 36

Answer

$16-9x^2$ Note that standard form would list the variables first in decreasing order of exponent, so another way to write this answer is: $-9x^2+16$.

Work Step by Step

$$(4-3x)(4+3x)$$ $$=(4\times 4)+(4\times 3x)+(-3x\times 4)+(-3x\times 3x)$$ $$=16+12x-12x-9x^2$$ $$=16-9x^2$$ Note that standard form would list the variables first in decreasing order of exponent, so another way to write this answer is: $$-9x^2+16$$
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