College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 29

Answer

$8x^5-40x^3+3x^2-15$

Work Step by Step

$$(8x^3+3)(x^2-5)$$ $$=(8x^3\times x^2)+(8x^3\times (-5))+(3\times x^2)+(3\times (-5))$$ $$=8x^5-40x^3+3x^2-15$$
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