College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 27

Answer

$15x^4-47x^2+28$

Work Step by Step

$$(5x^2-4)(3x^2-7)$$ $$=(5x^2\times 3x^2)+(5x^2\times (-7))+(-4\times 3x^2)+(-4\times (-7))$$ $$=15x^4-35x^2-12x^2+28$$ $$=15x^4-47x^2+28$$
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