## College Algebra (6th Edition)

$6x^3+10x^2+11x-8$; Degree 3
$$(8x^2+7x-5)-(3x^2-4x)-(-6x^3-5x^2+3)$$ $$=-(-6x^3)+(8x^2-3x^2-(-5x^2))+(7x-(-4x))+(-5-3)$$ $$=6x^3+(5x^2+5x^2)+(7x+4x)-8$$ $$=6x^3+10x^2+11x-8$$