## College Algebra (6th Edition)

Published by Pearson

# Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 92

#### Answer

$12x^\frac{17}{12}$

#### Work Step by Step

$$(3x^\frac{2}{3})(4x^\frac{3}{4})$$ $$=(3\times4)(x^\frac{2}{3} \times x^\frac{3}{4})$$ When two rational expressions with the same base are multiplied, add the exponents. $$=12x^{\frac{2}{3} + \frac{3}{4}}$$ When adding fractions, you need a common denominator, in this case, 12: $$=12x^{\frac{8}{12} + \frac{9}{12}}$$ $$=12x^\frac{17}{12}$$

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