College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 91

Answer

$14x^{\frac{7}{12}}$

Work Step by Step

$$(7x^{\frac{1}{3}})(2x^{\frac{1}{4}})$$ $$=(7\times2)(x^{\frac{1}{3}}\times x^{\frac{1}{4}})$$ When two rational expressions with the same base are multiplied, add the exponents. $$=14x^{\frac{1}{3} + \frac{1}{4}}$$ When adding fractions, you need a common denominator, in this case, 12: $$=14x^{\frac{4}{12}+\frac{3}{12}}$$ $$=14x^\frac{7}{12}$$
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