College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 81

Answer

$\sqrt2 + 2$

Work Step by Step

$$\sqrt2 + \sqrt[3]8$$ $$=\sqrt2 + 2$$ As these are not like terms (one is a radical, the other is an integer) they can not be combined.
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