College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 80

Answer

$-y\sqrt[3]{3x}$

Work Step by Step

$$\sqrt[3]{24xy^3} - y\sqrt[3]{81x}$$ $$=\sqrt[3]{8y^3\times3x} - y\sqrt[3]{27\times3x}$$ $$=2y\sqrt[3]{3x} - 3y\sqrt[3]{3x}$$ $$=(2y-3y)\sqrt[3]{3x}$$ $$=-y\sqrt[3]{3x}$$
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